What is the inverse of f(x)= x/4-(x^2)/(72)-1/8 ?

The inverse of f(x)= x/4-(x^2)/(72)-1/8 is -(-18+sqrt(-288x+288))/2 ,-(-18-sqrt(-288x+288))/2

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inverse of f(x)= x/4-(x^2)/(72)-1/8

inverse

f (x) = \frac{x}{4} - \frac{x ^{2}}{72} - \frac{1}{8}

- \frac{- 18 + - 288 x + 288}{2}, - \frac{- 18 - - 288 x + 288}{2}

Solution steps

y = \frac{x}{4} - \frac{x ^{2}}{72} - \frac{1}{8}

Replace

x

with

y

x = \frac{y}{4} - \frac{y ^{2}}{72} - \frac{1}{8}

Solve for

y, x = \frac{y}{4} - \frac{y ^{2}}{72} - \frac{1}{8}

- \frac{- 18 + - 288 x + 288}{2}, - \frac{- 18 - - 288 x + 288}{2}

y = 305 + 0.65 x

h (t) = - 16 t^{2} + 32 t + 5

x^{2} + 8 x - 3

2.5 t + 5.5

f (x) = \frac{( x + 4 )}{( x + 10 )}

What is the inverse of f(x)= x/4-(x^2)/(72)-1/8 ?
The inverse of f(x)= x/4-(x^2)/(72)-1/8 is -(-18+sqrt(-288x+288))/2 ,-(-18-sqrt(-288x+288))/2