What is the inverse of f(x)=8\sqrt[3]{x+4}-6 ?

The inverse of f(x)=8\sqrt[3]{x+4}-6 is -229/64+(x^3)/(512)+(9x^2)/(256)+(27x)/(128)

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inverse of f(x)=8\sqrt[3]{x+4}-6

inverse

f (x) = 8 3 x + 4 - 6

- \frac{229}{64} + \frac{x ^{3}}{512} + \frac{9 x ^{2}}{256} + \frac{27 x}{128}

Solution steps

y = 8 3 x + 4 - 6

Replace

x

with

y

x = 8 3 y + 4 - 6

Solve for

y, x = 8 3 y + 4 - 6

- \frac{229}{64} + \frac{x ^{3}}{512} + \frac{9 x ^{2}}{256} + \frac{27 x}{128}

y = 7 x + 3

\frac{x + 4}{- 4 x + 3}

sin (3), - \frac{π}{2} \leq x \leq \frac{π}{2}

tan (0.75)

- \frac{6}{7}

What is the inverse of f(x)=8\sqrt[3]{x+4}-6 ?
The inverse of f(x)=8\sqrt[3]{x+4}-6 is -229/64+(x^3)/(512)+(9x^2)/(256)+(27x)/(128)