What is the inverse of f(x)=((2x-3))/(x-5) ?

The inverse of f(x)=((2x-3))/(x-5) is (-3+5x)/(x-2)

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inverse of f(x)=((2x-3))/(x-5)

inverse

f (x) = \frac{( 2 x - 3 )}{x - 5}

\frac{- 3 + 5 x}{x - 2}

Solution steps

y = \frac{2 x - 3}{x - 5}

Replace

x

with

y

x = \frac{2 y - 3}{y - 5}

Solve for

y, x = \frac{2 y - 3}{y - 5}

\frac{- 3 + 5 x}{x - 2}

arccos (0)

\frac{x + 5}{x}

f (x) = 4 + 2 - x

f (x) = \frac{2}{x ^{2} - 1}

f (x) = e^{2 x} + e^{x} + 1

What is the inverse of f(x)=((2x-3))/(x-5) ?
The inverse of f(x)=((2x-3))/(x-5) is (-3+5x)/(x-2)