What is the inverse of f(x)=ln(x^2-1) ?

The inverse of f(x)=ln(x^2-1) is sqrt(e^x+1),-sqrt(e^x+1)

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inverse of f(x)=ln(x^2-1)

inverse

f (x) = ln (x^{2} - 1)

e^{x} + 1, - e^{x} + 1

Solution steps

y = ln (x^{2} - 1)

Replace

x

with

y

x = ln (y^{2} - 1)

Solve for

y, x = ln (y^{2} - 1)

e^{x} + 1, - e^{x} + 1

y = 4 x + 1

y = - 2 - x

f (x) = \frac{8 + 2 x}{7}

f (x) = 2 y + 3

f (x) = 6 (x^{- \frac{1}{3}})

What is the inverse of f(x)=ln(x^2-1) ?
The inverse of f(x)=ln(x^2-1) is sqrt(e^x+1),-sqrt(e^x+1)