What is the inverse of f(x)=((4x+1))/(3x-5) ?

The inverse of f(x)=((4x+1))/(3x-5) is (1+5x)/(3x-4)

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inverse of f(x)=((4x+1))/(3x-5)

inverse

f (x) = \frac{( 4 x + 1 )}{3 x - 5}

\frac{1 + 5 x}{3 x - 4}

Solution steps

y = \frac{4 x + 1}{3 x - 5}

Replace

x

with

y

x = \frac{4 y + 1}{3 y - 5}

Solve for

y, x = \frac{4 y + 1}{3 y - 5}

\frac{1 + 5 x}{3 x - 4}

lo g_{10} (- 4.5)

f (x) = \frac{63}{4 x - 1}

- 2 (x - 3)^{2} - 6

f (x) = - \frac{2}{5} x - 3

y = 1 0^{0.5 x}

What is the inverse of f(x)=((4x+1))/(3x-5) ?
The inverse of f(x)=((4x+1))/(3x-5) is (1+5x)/(3x-4)