What is the inverse of f(x)=sqrt(17-x^2) ?

The inverse of f(x)=sqrt(17-x^2) is sqrt(-x^2+17),-sqrt(-x^2+17)

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inverse of f(x)=sqrt(17-x^2)

inverse

f (x) = 17 - x^{2}

- x^{2} + 17, - - x^{2} + 17

Solution steps

y = 17 - x^{2}

Replace

x

with

y

x = 17 - y^{2}

Solve for

y, x = 17 - y^{2}

- x^{2} + 17, - - x^{2} + 17

f (x) = 3 (sin (x^{2}) - 2)

y = 9 x

f (x) = \frac{( 2 x - 3 )}{x + 5}

(x + 1)^{2} - 4

\frac{1}{3 x + 2}

What is the inverse of f(x)=sqrt(17-x^2) ?
The inverse of f(x)=sqrt(17-x^2) is sqrt(-x^2+17),-sqrt(-x^2+17)