What is the inverse of f(x)=\sqrt[3]{x+9}-2 ?

The inverse of f(x)=\sqrt[3]{x+9}-2 is x^3+6x^2+12x-1

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inverse of f(x)=\sqrt[3]{x+9}-2

inverse

f (x) = 3 x + 9 - 2

x^{3} + 6 x^{2} + 12 x - 1

Solution steps

y = 3 x + 9 - 2

Replace

x

with

y

x = 3 y + 9 - 2

Solve for

y, x = 3 y + 9 - 2

x^{3} + 6 x^{2} + 12 x - 1

f (x) = \frac{3 x - 4}{5 x + 6}

f (x) = a (r) = 3 r + 15

f (x) = \frac{4 x}{3 x - 1}

f (x) = \frac{3 x + 1}{11 x - 2}

f (x) = - 5 t^{2} + 10 t + 20

What is the inverse of f(x)=\sqrt[3]{x+9}-2 ?
The inverse of f(x)=\sqrt[3]{x+9}-2 is x^3+6x^2+12x-1