What is the inverse of 1/(sqrt(2pi))e^{-1/2 x^2} ?

The inverse of 1/(sqrt(2pi))e^{-1/2 x^2} is sqrt(-ln(2pix^2)),-sqrt(-ln(2pix^2))

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inverse of 1/(sqrt(2pi))e^{-1/2 x^2}

inverse

\frac{1}{2 π} e^{- \frac{1}{2} x^{2}}

- ln (2 π x^{2}), - - ln (2 π x^{2})

Solution steps

y = \frac{1}{2 π} e^{- \frac{1}{2} x^{2}}

Replace

x

with

y

x = \frac{1}{2 π} e^{- \frac{1}{2} y^{2}}

Solve for

y, x = \frac{1}{2 π} e^{- \frac{1}{2} y^{2}}

- ln (2 π x^{2}), - - ln (2 π x^{2})

f (x) = \frac{- 2 x + 5}{2 x + 3}

f (x) = 54 x - 13

h (x) = \frac{2}{x + 5}

f (x) = - 6 x^{5} + 3

f (x) = - \frac{x ^{2}}{600} + \frac{x}{10} - \frac{1}{2}

What is the inverse of 1/(sqrt(2pi))e^{-1/2 x^2} ?
The inverse of 1/(sqrt(2pi))e^{-1/2 x^2} is sqrt(-ln(2pix^2)),-sqrt(-ln(2pix^2))