What is the inverse of f(x)=(x^4+2)/3 ?

The inverse of f(x)=(x^4+2)/3 is \sqrt[4]{3x-2},-\sqrt[4]{3x-2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x^4+2)/3

inverse

f (x) = \frac{x ^{4} + 2}{3}

4 3 x - 2, - 4 3 x - 2

Solution steps

y = \frac{x ^{4} + 2}{3}

Replace

x

with

y

x = \frac{y ^{4} + 2}{3}

Solve for

y, x = \frac{y ^{4} + 2}{3}

4 3 x - 2, - 4 3 x - 2

f (x) = sinh^{2} (\frac{x}{x ^{4}})

f (x) = 2^{x^{2} + 2 x}

\frac{3 x}{6}

f (x) = \frac{x ^{2} + 1 ^{2} - 1}{x ^{2}}

f (x) = lo g_{10} (sin (x))

What is the inverse of f(x)=(x^4+2)/3 ?
The inverse of f(x)=(x^4+2)/3 is \sqrt[4]{3x-2},-\sqrt[4]{3x-2}