What is the inverse of g(62)=(100)/(x-12)+8 ?

The inverse of g(62)=(100)/(x-12)+8 is (-12x-4)/(-x+8)

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inverse of g(62)=(100)/(x-12)+8

inverse

g (62) = \frac{100}{x - 12} + 8

\frac{- 12 x - 4}{- x + 8}

Solution steps

y = \frac{100}{x - 12} + 8

Replace

x

with

y

x = \frac{100}{y - 12} + 8

Solve for

y, x = \frac{100}{y - 12} + 8

\frac{- 12 x - 4}{- x + 8}

f (x) = \frac{x + x ^{2}}{1 - x}

ln (ln (ln (x)))

\frac{x + 4}{x}

f (x) = \frac{x + 2}{2} - 1

y = z^{- \frac{1}{2}}

What is the inverse of g(62)=(100)/(x-12)+8 ?
The inverse of g(62)=(100)/(x-12)+8 is (-12x-4)/(-x+8)