What is the inverse of f(x)=\sqrt[3]{x-9}+2 ?

The inverse of f(x)=\sqrt[3]{x-9}+2 is x^3-6x^2+12x+1

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inverse of f(x)=\sqrt[3]{x-9}+2

inverse

x^{3} - 6 x^{2} + 12 x + 1

Solution steps

Replace

x

with

y

Solve for

x^{3} - 6 x^{2} + 12 x + 1

f (x) = \frac{x + 4}{x - 6}

f (x) = \frac{1}{3 y - 2}

f (x) = 2.1786 x + 25.3

- 3 x + \frac{6}{7}

f (x) = \frac{6 x}{9 - 5 x}

What is the inverse of f(x)=\sqrt[3]{x-9}+2 ?
The inverse of f(x)=\sqrt[3]{x-9}+2 is x^3-6x^2+12x+1