What is the inverse of f(x)= 3/4 sqrt(x+2)-1 ?

The inverse of f(x)= 3/4 sqrt(x+2)-1 is (16x^2+32x+16)/9-2

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inverse of f(x)= 3/4 sqrt(x+2)-1

inverse

f (x) = \frac{3}{4} x + 2 - 1

\frac{16 x ^{2} + 32 x + 16}{9} - 2

Solution steps

y = \frac{3}{4} x + 2 - 1

Replace

x

with

y

x = \frac{3}{4} y + 2 - 1

Solve for

y, x = \frac{3}{4} y + 2 - 1

\frac{16 x ^{2} + 32 x + 16}{9} - 2

\frac{9 x ^{2} - 144}{x ^{2} - 144}

lo g_{2} (4 x + 6)

f (x) = - 2 (x - 3) 2 - 6

s^{2} + 4.5 s + 9

f (x) = cos (x - 1) + 2

What is the inverse of f(x)= 3/4 sqrt(x+2)-1 ?
The inverse of f(x)= 3/4 sqrt(x+2)-1 is (16x^2+32x+16)/9-2