What is the inverse of y=-1/5 (x-4)^2+2.3 ?

The inverse of y=-1/5 (x-4)^2+2.3 is sqrt(-5x+11.5)+4,-sqrt(-5x+11.5)+4

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inverse of y=-1/5 (x-4)^2+2.3

inverse

y = - \frac{1}{5} (x - 4)^{2} + 2.3

- 5 x + 11.5 + 4, - - 5 x + 11.5 + 4

Solution steps

y = - \frac{1}{5} (x - 4)^{2} + 2.3

Replace

x

with

y

x = - \frac{1}{5} (y - 4)^{2} + 2.3

Solve for

y, x = - \frac{1}{5} (y - 4)^{2} + 2.3

- 5 x + 11.5 + 4, - - 5 x + 11.5 + 4

(9 - x)^{3}

\frac{5 t ^{2}}{2}

f (x) = \frac{( 2 + x )}{( 2 - x )}

f (x) = 1 0^{(- 1 \cdot \frac{( x + 5 )}{2})}

f (x) = ln (x - 1)

What is the inverse of y=-1/5 (x-4)^2+2.3 ?
The inverse of y=-1/5 (x-4)^2+2.3 is sqrt(-5x+11.5)+4,-sqrt(-5x+11.5)+4