What is the inverse of y=-4.9(x+3)^2+45.8 ?

The inverse of y=-4.9(x+3)^2+45.8 is sqrt(-(10x-458)/(49))-3,-sqrt(-(10x-458)/(49))-3

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inverse of y=-4.9(x+3)^2+45.8

inverse

y = - 4.9 (x + 3)^{2} + 45.8

- \frac{10 x - 458}{49} - 3, - - \frac{10 x - 458}{49} - 3

Solution steps

y = - 4.9 (x + 3)^{2} + 45.8

Replace

x

with

y

x = - 4.9 (y + 3)^{2} + 45.8

Solve for

y, x = - 4.9 (y + 3)^{2} + 45.8

- \frac{10 x - 458}{49} - 3, - - \frac{10 x - 458}{49} - 3

f (x) = \frac{x + 6}{2}

f (x) = - \frac{( x + 1 )}{2}

f (x) = \frac{25}{x ^{2}}, x > 0

10 cos (\frac{2}{5} x)

f (x) = (x - 11)^{2}, [11, \infty]

What is the inverse of y=-4.9(x+3)^2+45.8 ?
The inverse of y=-4.9(x+3)^2+45.8 is sqrt(-(10x-458)/(49))-3,-sqrt(-(10x-458)/(49))-3