What is the inverse of f(x)=4(x-3)^5+21 ?

The inverse of f(x)=4(x-3)^5+21 is \sqrt[5]{(x-21)/4}+3

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inverse of f(x)=4(x-3)^5+21

inverse

f (x) = 4 (x - 3)^{5} + 21

Solution steps

y = 4 (x - 3)^{5} + 21

Replace

x

with

y

x = 4 (y - 3)^{5} + 21

Solve for

y, x = 4 (y - 3)^{5} + 21

cos (π x - 2) - 1

f (x) = lo g_{e} (x - 2)

5 + 2 sin (\frac{x - 1}{x + 1})

4 - e^{2 x}

f (x) = \frac{( - 2 x - 5 )}{( - 8 x + 5 )}

What is the inverse of f(x)=4(x-3)^5+21 ?
The inverse of f(x)=4(x-3)^5+21 is \sqrt[5]{(x-21)/4}+3