What is the inverse of f(x)=log_{1/2}(x+1)+4 ?

The inverse of f(x)=log_{1/2}(x+1)+4 is (1/2)^{x-4}-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=log_{1/2}(x+1)+4

inverse

f (x) = lo g_{\frac{1}{2}} (x + 1) + 4

(\frac{1}{2})^{x - 4} - 1

Solution steps

y = lo g_{\frac{1}{2}} (x + 1) + 4

Replace

x

with

y

x = lo g_{\frac{1}{2}} (y + 1) + 4

Solve for

y, x = lo g_{\frac{1}{2}} (y + 1) + 4

(\frac{1}{2})^{x - 4} - 1

\frac{2 x + 3}{1 - x}

f (x) = \frac{5 - x}{3 x + 4}

f (x) = 2 \cdot 4^{x}

f (x) = x^{2} - 4 x + 8

f (x) = 11 x - 8

What is the inverse of f(x)=log_{1/2}(x+1)+4 ?
The inverse of f(x)=log_{1/2}(x+1)+4 is (1/2)^{x-4}-1