What is the inverse of f(x)=(x^2-9)/(6x^2) ?

The inverse of f(x)=(x^2-9)/(6x^2) is sqrt(-9/(6x-1)),-sqrt(-9/(6x-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x^2-9)/(6x^2)

inverse

f (x) = \frac{x ^{2} - 9}{6 x ^{2}}

- \frac{9}{6 x - 1}, - - \frac{9}{6 x - 1}

Solution steps

y = \frac{x ^{2} - 9}{6 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 9}{6 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 9}{6 y ^{2}}

- \frac{9}{6 x - 1}, - - \frac{9}{6 x - 1}

f (x) = arccos (\frac{5 x}{x + 12})

f (x) = \frac{- x - 1}{2 x - 1}

1 - 2 2 x - 5

f (x) = sin (θ)

What is the inverse of f(x)=(x^2-9)/(6x^2) ?
The inverse of f(x)=(x^2-9)/(6x^2) is sqrt(-9/(6x-1)),-sqrt(-9/(6x-1))