What is the inverse of f(x)=2x^2-5x ?

The inverse of f(x)=2x^2-5x is (5+sqrt(25+8x))/4 ,(5-sqrt(25+8x))/4

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inverse of f(x)=2x^2-5x

inverse

f (x) = 2 x^{2} - 5 x

\frac{5 + 25 + 8 x}{4}, \frac{5 - 25 + 8 x}{4}

Solution steps

y = 2 x^{2} - 5 x

Replace

x

with

y

x = 2 y^{2} - 5 y

Solve for

y, x = 2 y^{2} - 5 y

\frac{5 + 25 + 8 x}{4}, \frac{5 - 25 + 8 x}{4}

f (x) = - 4 x - 2

f (x) = \frac{3}{3 x + 4}

f (x) = \frac{3}{3 x + 2}

f (x) = 4 (x + 3) - 2

\frac{x - 2}{3 + x}

What is the inverse of f(x)=2x^2-5x ?
The inverse of f(x)=2x^2-5x is (5+sqrt(25+8x))/4 ,(5-sqrt(25+8x))/4