What is the inverse of f(x)= 8/(3+x^2) ?

The inverse of f(x)= 8/(3+x^2) is sqrt((8-3x)/x),-sqrt((8-3x)/x)

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inverse of f(x)= 8/(3+x^2)

inverse

f (x) = \frac{8}{3 + x ^{2}}

\frac{8 - 3 x}{x}, - \frac{8 - 3 x}{x}

Solution steps

y = \frac{8}{3 + x ^{2}}

Replace

x

with

y

x = \frac{8}{3 + y ^{2}}

Solve for

y, x = \frac{8}{3 + y ^{2}}

\frac{8 - 3 x}{x}, - \frac{8 - 3 x}{x}

f (x) = - ln (x + 2) + 1

f (x) = 4 + 4 x - 8

f (x) = 9 x^{2} - 12, x \geq 0

f (x) = \frac{1}{x + 5}

\frac{3 x + 10}{x + 3}

What is the inverse of f(x)= 8/(3+x^2) ?
The inverse of f(x)= 8/(3+x^2) is sqrt((8-3x)/x),-sqrt((8-3x)/x)