What is the inverse of y=((3x-7))/((9x+1)) ?

The inverse of y=((3x-7))/((9x+1)) is (-7-x)/(3(-1+3x))

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inverse of y=((3x-7))/((9x+1))

inverse

y = \frac{( 3 x - 7 )}{( 9 x + 1 )}

\frac{- 7 - x}{3 ( - 1 + 3 x )}

Solution steps

y = \frac{3 x - 7}{9 x + 1}

Replace

x

with

y

x = \frac{3 y - 7}{9 y + 1}

Solve for

y, x = \frac{3 y - 7}{9 y + 1}

\frac{- 7 - x}{3 ( - 1 + 3 x )}

z^{- 1} (\frac{2 z}{( z - 2 ) ^{2}})

y = \frac{x}{x + 6}

\frac{1}{2} - e^{1 - \frac{1}{2} x}

f (A) = 2 π r^{2} + 2 π r

f (x) = \frac{15}{2} lo g_{3} (x - 9) + 4

What is the inverse of y=((3x-7))/((9x+1)) ?
The inverse of y=((3x-7))/((9x+1)) is (-7-x)/(3(-1+3x))