What is the inverse of f(x)=(3x-7)/(9x+1) ?

The inverse of f(x)=(3x-7)/(9x+1) is (-7-x)/(3(-1+3x))

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inverse of f(x)=(3x-7)/(9x+1)

inverse

f (x) = \frac{3 x - 7}{9 x + 1}

\frac{- 7 - x}{3 ( - 1 + 3 x )}

Solution steps

y = \frac{3 x - 7}{9 x + 1}

Replace

x

with

y

x = \frac{3 y - 7}{9 y + 1}

Solve for

y, x = \frac{3 y - 7}{9 y + 1}

\frac{- 7 - x}{3 ( - 1 + 3 x )}

\frac{x - 2}{- 2 x + 1}

f (x) = 2.1783 x + 25.2

f (x) = \frac{1}{x - 3} x

f (x) = - 4 x + 20

\frac{x + 9}{x - 3}

What is the inverse of f(x)=(3x-7)/(9x+1) ?
The inverse of f(x)=(3x-7)/(9x+1) is (-7-x)/(3(-1+3x))