What is the inverse of-3(x+2)^2+1 ?

The inverse of-3(x+2)^2+1 is sqrt(-(x-1)/3)-2,-sqrt(-(x-1)/3)-2

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inverse of-3(x+2)^2+1

inverse

- 3 (x + 2)^{2} + 1

- \frac{x - 1}{3} - 2, - - \frac{x - 1}{3} - 2

Solution steps

y = - 3 (x + 2)^{2} + 1

Replace

x

with

y

x = - 3 (y + 2)^{2} + 1

Solve for

y, x = - 3 (y + 2)^{2} + 1

- \frac{x - 1}{3} - 2, - - \frac{x - 1}{3} - 2

\frac{x + 5}{x - 7}

f (x) = 4 + 3 x

f (x) = \frac{3 x}{4 x - 7}

f (x) = - \frac{16 + x}{4}

f (x) = ln (3 x) + 2

What is the inverse of-3(x+2)^2+1 ?
The inverse of-3(x+2)^2+1 is sqrt(-(x-1)/3)-2,-sqrt(-(x-1)/3)-2