What is the inverse of f(x)=(x-12)^2,[12,infinity ] ?

The inverse of f(x)=(x-12)^2,[12,infinity ] is sqrt(x)+12,-sqrt(x)+12

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inverse of f(x)=(x-12)^2,[12,infinity ]

inverse

f (x) = (x - 12)^{2}, [12, \infty]

x + 12, - x + 12

Solution steps

y = (x - 12)^{2}

Replace

x

with

y

x = (y - 12)^{2}

Solve for

y, x = (y - 12)^{2}

x + 12, - x + 12

f (x) = \frac{6 x - 1}{2 x - 4}

m (d) = 40 (d - 35)

\frac{- x - 13}{7}

3 - 4 x

f (x) = \frac{e ^{x}}{e ^{x} - 1}

What is the inverse of f(x)=(x-12)^2,[12,infinity ] ?
The inverse of f(x)=(x-12)^2,[12,infinity ] is sqrt(x)+12,-sqrt(x)+12