What is the inverse of f(x)=400-16x^2 ?

The inverse of f(x)=400-16x^2 is sqrt(-(x-400)/(16)),-sqrt(-(x-400)/(16))

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inverse of f(x)=400-16x^2

inverse

f (x) = 400 - 16 x^{2}

- \frac{x - 400}{16}, - - \frac{x - 400}{16}

Solution steps

y = 400 - 16 x^{2}

Replace

x

with

y

x = 400 - 16 y^{2}

Solve for

y, x = 400 - 16 y^{2}

- \frac{x - 400}{16}, - - \frac{x - 400}{16}

x \frac{1}{2}

3 + x

f (x) = f (x) = 3 x - 5 x

- \frac{2}{3} x + 1

f (x) = \frac{x + 5}{x + 13}

What is the inverse of f(x)=400-16x^2 ?
The inverse of f(x)=400-16x^2 is sqrt(-(x-400)/(16)),-sqrt(-(x-400)/(16))