What is the inverse of f(x)=6y=(x-4)^2-2/3+12 ?

The inverse of f(x)=6y=(x-4)^2-2/3+12 is sqrt((3x-34)/3)+4,-sqrt((3x-34)/3)+4

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inverse of f(x)=6y=(x-4)^2-2/3+12

inverse

f (x) = 6 y = (x - 4)^{2} - \frac{2}{3} + 12

\frac{3 x - 34}{3} + 4, - \frac{3 x - 34}{3} + 4

Solution steps

y = (x - 4)^{2} - \frac{2}{3} + 12

Replace

x

with

y

x = (y - 4)^{2} - \frac{2}{3} + 12

Solve for

y, x = (y - 4)^{2} - \frac{2}{3} + 12

\frac{3 x - 34}{3} + 4, - \frac{3 x - 34}{3} + 4

sin (x)

f (x) = \frac{1 - 2 x}{5 x - 3}

\frac{1}{x - 4}

f (x) = \frac{x - 5}{2 x - 7}

4 - 2

What is the inverse of f(x)=6y=(x-4)^2-2/3+12 ?
The inverse of f(x)=6y=(x-4)^2-2/3+12 is sqrt((3x-34)/3)+4,-sqrt((3x-34)/3)+4