What is the inverse of f(x)=4+4\sqrt[3]{x} ?

The inverse of f(x)=4+4\sqrt[3]{x} is (x^3}{64}-(3x^2)/(16)+\frac{3x)/4-1

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inverse of f(x)=4+4\sqrt[3]{x}

inverse

\frac{x ^{3}}{64} - \frac{3 x ^{2}}{16} + \frac{3 x}{4} - 1

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3}}{64} - \frac{3 x ^{2}}{16} + \frac{3 x}{4} - 1

7 x - 21

f (x) = 2 + e^{- x}

f (x) = \frac{1}{( 1 - x ) ^{2}}

f (x) = \frac{- 5 x - 2}{7}

f (x) = x^{2} - 17, x \geq 0

What is the inverse of f(x)=4+4\sqrt[3]{x} ?
The inverse of f(x)=4+4\sqrt[3]{x} is (x^3}{64}-(3x^2)/(16)+\frac{3x)/4-1