What is the inverse of f(x)=(1-x^3)^{1/3} ?

The inverse of f(x)=(1-x^3)^{1/3} is cube root of-x^3+1

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inverse of f(x)=(1-x^3)^{1/3}

inverse

f (x) = (1 - x^{3})^{\frac{1}{3}}

3 - x^{3} + 1

Solution steps

y = (1 - x^{3})^{\frac{1}{3}}

Replace

x

with

y

x = (1 - y^{3})^{\frac{1}{3}}

Solve for

y, x = (1 - y^{3})^{\frac{1}{3}}

3 - x^{3} + 1

7 - 9 x

f (x) = - 5 cos (3 x)

\frac{3 + 5 x}{x}

y = 4 - x

f (x) = - 6 x + 13

What is the inverse of f(x)=(1-x^3)^{1/3} ?
The inverse of f(x)=(1-x^3)^{1/3} is cube root of-x^3+1