What is the inverse of f(x)=-13/4 (7/2)^{x+11}-5 ?

The inverse of f(x)=-13/4 (7/2)^{x+11}-5 is (ln(-\frac{4x+20)/(13))}{ln(7/2)}-11

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inverse of f(x)=-13/4 (7/2)^{x+11}-5

inverse

f (x) = - \frac{13}{4} (\frac{7}{2})^{x + 11} - 5

\frac{ln ( - \frac{4 x + 20}{13} )}{ln ( \frac{7}{2} )} - 11

Solution steps

y = - \frac{13}{4} (\frac{7}{2})^{x + 11} - 5

Replace

x

with

y

x = - \frac{13}{4} (\frac{7}{2})^{y + 11} - 5

Solve for

y, x = - \frac{13}{4} (\frac{7}{2})^{y + 11} - 5

\frac{ln ( - \frac{4 x + 20}{13} )}{ln ( \frac{7}{2} )} - 11

2^{x} + 1

f (x) = \frac{x + 9}{x + 3}

f (x) = \frac{e ^{x}}{5 + e ^{2}}

y = 3 x^{2} + 2

2 + 3 - x

What is the inverse of f(x)=-13/4 (7/2)^{x+11}-5 ?
The inverse of f(x)=-13/4 (7/2)^{x+11}-5 is (ln(-\frac{4x+20)/(13))}{ln(7/2)}-11