What is the inverse of f(x)=-16x^2+63x+5 ?

The inverse of f(x)=-16x^2+63x+5 is -(-63+sqrt(-64x+4289))/(32),-(-63-sqrt(-64x+4289))/(32)

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inverse of f(x)=-16x^2+63x+5

inverse

f (x) = - 16 x^{2} + 63 x + 5

- \frac{- 63 + - 64 x + 4289}{32}, - \frac{- 63 - - 64 x + 4289}{32}

Solution steps

y = - 16 x^{2} + 63 x + 5

Replace

x

with

y

x = - 16 y^{2} + 63 y + 5

Solve for

y, x = - 16 y^{2} + 63 y + 5

- \frac{- 63 + - 64 x + 4289}{32}, - \frac{- 63 - - 64 x + 4289}{32}

10 x^{3} - 12

f (x) = 100 \cdot 2^{\frac{x}{2}}

f (x) = 3 - ln (x^{2} + 2 x - 3)

f (x) = x + (\frac{4}{x})

f (x) = \frac{10 x - 6}{2 x - 2}

What is the inverse of f(x)=-16x^2+63x+5 ?
The inverse of f(x)=-16x^2+63x+5 is -(-63+sqrt(-64x+4289))/(32),-(-63-sqrt(-64x+4289))/(32)