What is the inverse of f(x)=-2(x+1)^2-5 ?

The inverse of f(x)=-2(x+1)^2-5 is sqrt(-(x+5)/2)-1,-sqrt(-(x+5)/2)-1

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inverse of f(x)=-2(x+1)^2-5

inverse

f (x) = - 2 (x + 1)^{2} - 5

- \frac{x + 5}{2} - 1, - - \frac{x + 5}{2} - 1

Solution steps

y = - 2 (x + 1)^{2} - 5

Replace

x

with

y

x = - 2 (y + 1)^{2} - 5

Solve for

y, x = - 2 (y + 1)^{2} - 5

- \frac{x + 5}{2} - 1, - - \frac{x + 5}{2} - 1

f (x) = \frac{9 x}{4 x - 7}

5 - 9 x

- 3 (x + 6)

f (x) = sin (880 π x)

f (x) = x + 4 (x - 5) 2

What is the inverse of f(x)=-2(x+1)^2-5 ?
The inverse of f(x)=-2(x+1)^2-5 is sqrt(-(x+5)/2)-1,-sqrt(-(x+5)/2)-1