What is the inverse of f(x)=(x-18)^2 ?

The inverse of f(x)=(x-18)^2 is sqrt(x)+18,-sqrt(x)+18

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inverse of f(x)=(x-18)^2

inverse

f (x) = (x - 18)^{2}

x + 18, - x + 18

Solution steps

y = (x - 18)^{2}

Replace

x

with

y

x = (y - 18)^{2}

Solve for

y, x = (y - 18)^{2}

x + 18, - x + 18

h (x) = (x - 2)^{3}

f (x) = - x^{2} - 9

f (x) = 6 ln (x - 5)

y = 2 x + 1

f (r) = 2 π r^{2} + 12 π r

What is the inverse of f(x)=(x-18)^2 ?
The inverse of f(x)=(x-18)^2 is sqrt(x)+18,-sqrt(x)+18