What is the inverse of h(x)=(5x-3)/(2x+1) ?

The inverse of h(x)=(5x-3)/(2x+1) is (-3-x)/(2x-5)

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inverse of h(x)=(5x-3)/(2x+1)

inverse

h (x) = \frac{5 x - 3}{2 x + 1}

\frac{- 3 - x}{2 x - 5}

Solution steps

y = \frac{5 x - 3}{2 x + 1}

Replace

x

with

y

x = \frac{5 y - 3}{2 y + 1}

Solve for

y, x = \frac{5 y - 3}{2 y + 1}

\frac{- 3 - x}{2 x - 5}

f (x) = 2 - \frac{3 x}{2}

4 x + 5 - 3

f (x) = \frac{3 x - 1}{5}

f (x) = 15 x^{2} + 2 x - 8

f (x) = 1980 \cdot 0.9 7^{x}

What is the inverse of h(x)=(5x-3)/(2x+1) ?
The inverse of h(x)=(5x-3)/(2x+1) is (-3-x)/(2x-5)