What is the inverse of f(x)=x^2+4x-6,x<= 2 ?

The inverse of f(x)=x^2+4x-6,x<= 2 is -2+sqrt(x+10),-sqrt(x+10)-2

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inverse of f(x)=x^2+4x-6,x<= 2

inverse

f (x) = x^{2} + 4 x - 6, x \leq 2

- 2 + x + 10, - x + 10 - 2

Solution steps

y = x^{2} + 4 x - 6

Replace

x

with

y

x = y^{2} + 4 y - 6

Solve for

y, x = y^{2} + 4 y - 6

- 2 + x + 10, - x + 10 - 2

f (x) = 5 \cdot x + \frac{π}{4}

f (x) = \frac{4 - x}{3 + x}

f (x) = \frac{1 x - 1}{5 x - 4}

f (x) = - 10 x + 2

f (x) = x^{2} - 8, x \leq 0

What is the inverse of f(x)=x^2+4x-6,x<= 2 ?
The inverse of f(x)=x^2+4x-6,x<= 2 is -2+sqrt(x+10),-sqrt(x+10)-2