What is the inverse of f(x)=(1^{-x})/3 ?

The inverse of f(x)=(1^{-x})/3 is None

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inverse of f(x)=(1^{-x})/3

inverse

f (x) = \frac{1 ^{- x}}{3}

None

Solution steps

y = \frac{1 ^{- x}}{3}

Replace

x

with

y

x = \frac{1 ^{- y}}{3}

Solve for

y, x = \frac{1 ^{- y}}{3}

Therefore, there are no inverse functions for

\frac{1 ^{- x}}{3}

None

\frac{s ^{2} - 10 s + 21}{( s - 3 ) ^{2} ( s + 3 )}

f (x) = x^{2} - x^{4}

f (x) = 1 x + 1

f (x) = 3 8 x + 4

f (x) = \frac{2}{x + 5} = 3