What is the inverse of f(x)=(x^2)/2+1 ?

The inverse of f(x)=(x^2)/2+1 is sqrt(2x-2),-sqrt(2x-2)

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inverse of f(x)=(x^2)/2+1

inverse

f (x) = \frac{x ^{2}}{2} + 1

2 x - 2, - 2 x - 2

Solution steps

y = \frac{x ^{2}}{2} + 1

Replace

x

with

y

x = \frac{y ^{2}}{2} + 1

Solve for

y, x = \frac{y ^{2}}{2} + 1

2 x - 2, - 2 x - 2

f (- 2) = 15 - x^{2}

f (x) = \frac{x + 10}{x + 6}

f (x) = \frac{1}{\frac{y}{2} - 2}

f (x) = 5 - x^{3} x - 4

tan (654 6^{\circ})

What is the inverse of f(x)=(x^2)/2+1 ?
The inverse of f(x)=(x^2)/2+1 is sqrt(2x-2),-sqrt(2x-2)