What is the inverse of ((1))/((x-2))+3,x>2 ?

The inverse of ((1))/((x-2))+3,x>2 is (2x-5)/(x-3)

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inverse of ((1))/((x-2))+3,x>2

inverse

\frac{( 1 )}{( x - 2 )} + 3, x > 2

\frac{2 x - 5}{x - 3}

Solution steps

y = \frac{1}{x - 2} + 3

Replace

x

with

y

x = \frac{1}{y - 2} + 3

Solve for

y, x = \frac{1}{y - 2} + 3

\frac{2 x - 5}{x - 3}

x^{2} - 4 x + 6

f (x) = ln^{3} (x)

f (x) = \frac{ln ( x - 4 )}{ln ( 3 )}

\frac{( 2 x - 1 )}{x + 2}

lo g_{5} (x + 6) - 7

What is the inverse of ((1))/((x-2))+3,x>2 ?
The inverse of ((1))/((x-2))+3,x>2 is (2x-5)/(x-3)