What is the inverse of e^{t^2+t/(50)} ?

The inverse of e^{t^2+t/(50)} is (-1+sqrt(1+10000ln(t)))/(100),(-1-sqrt(1+10000ln(t)))/(100)

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inverse of e^{t^2+t/(50)}

inverse

e^{t^{2} + \frac{t}{50}}

\frac{- 1 + 1 + 10000 ln ( t )}{100}, \frac{- 1 - 1 + 10000 ln ( t )}{100}

Solution steps

y = e^{t^{2} + \frac{t}{50}}

Replace

t

with

y

t = e^{y^{2} + \frac{y}{50}}

Solve for

y, t = e^{y^{2} + \frac{y}{50}}

\frac{- 1 + 1 + 10000 ln ( t )}{100}, \frac{- 1 - 1 + 10000 ln ( t )}{100}

f (x) = 3 - x - 2

f (x) = 2 (- x^{3}) - 2

3 a^{5 x - 1} + 1

\frac{3 x}{8 - 5 x}

y = \frac{1}{3} (x + 5) - 3

What is the inverse of e^{t^2+t/(50)} ?
The inverse of e^{t^2+t/(50)} is (-1+sqrt(1+10000ln(t)))/(100),(-1-sqrt(1+10000ln(t)))/(100)