What is the inverse of f(x)=4x^2+36x ?

The inverse of f(x)=4x^2+36x is (-9+sqrt(x+81))/2 ,-(sqrt(x+81)+9)/2

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inverse of f(x)=4x^2+36x

inverse

f (x) = 4 x^{2} + 36 x

\frac{- 9 + x + 81}{2}, - \frac{x + 81 + 9}{2}

Solution steps

y = 4 x^{2} + 36 x

Replace

x

with

y

x = 4 y^{2} + 36 y

Solve for

y, x = 4 y^{2} + 36 y

\frac{- 9 + x + 81}{2}, - \frac{x + 81 + 9}{2}

364

\frac{4 x + 3}{2 x + 5}

f (x) = 1 + x + x^{2}

y = \frac{1}{x + 1}

f (x) = - 7 x + 15

What is the inverse of f(x)=4x^2+36x ?
The inverse of f(x)=4x^2+36x is (-9+sqrt(x+81))/2 ,-(sqrt(x+81)+9)/2