What is the inverse of f(x)=2sqrt(x-9)+1 ?

The inverse of f(x)=2sqrt(x-9)+1 is (x^2+1)/4-x/2+9

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inverse of f(x)=2sqrt(x-9)+1

inverse

f (x) = 2 x - 9 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 9

Solution steps

y = 2 x - 9 + 1

Replace

x

with

y

x = 2 y - 9 + 1

Solve for

y, x = 2 y - 9 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 9

\frac{5 x}{6} + 9

\frac{3 x + 1}{x - 1}

f (x) = \frac{2}{x + 5} + 3

f (x) = 2 \cdot y

lo g_{e} (x - 3)

What is the inverse of f(x)=2sqrt(x-9)+1 ?
The inverse of f(x)=2sqrt(x-9)+1 is (x^2+1)/4-x/2+9