What is the inverse of f(x)=3x^2-2x ?

The inverse of f(x)=3x^2-2x is (1+sqrt(3x+1))/3 ,(1-sqrt(3x+1))/3

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inverse of f(x)=3x^2-2x

inverse

f (x) = 3 x^{2} - 2 x

\frac{1 + 3 x + 1}{3}, \frac{1 - 3 x + 1}{3}

Solution steps

y = 3 x^{2} - 2 x

Replace

x

with

y

x = 3 y^{2} - 2 y

Solve for

y, x = 3 y^{2} - 2 y

\frac{1 + 3 x + 1}{3}, \frac{1 - 3 x + 1}{3}

f (x) = \frac{x - 2}{2 x + 8}

y = e^{1 - x}

y = \frac{x}{6} + 2

3^{x} + 6

What is the inverse of f(x)=3x^2-2x ?
The inverse of f(x)=3x^2-2x is (1+sqrt(3x+1))/3 ,(1-sqrt(3x+1))/3