What is the inverse of f(x)=3x^2-13 ?

The inverse of f(x)=3x^2-13 is sqrt((x+13)/3),-sqrt((x+13)/3)

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inverse of f(x)=3x^2-13

inverse

f (x) = 3 x^{2} - 13

\frac{x + 13}{3}, - \frac{x + 13}{3}

Solution steps

y = 3 x^{2} - 13

Replace

x

with

y

x = 3 y^{2} - 13

Solve for

y, x = 3 y^{2} - 13

\frac{x + 13}{3}, - \frac{x + 13}{3}

f (x) = \frac{( x - 1 )}{x + 5}

cos (\frac{32}{51})

f (x) = - sin (x)

\frac{5 x + 8}{1 - 6 x}

f (x) = \frac{( 5 x - 8 )}{3 x + 1}

What is the inverse of f(x)=3x^2-13 ?
The inverse of f(x)=3x^2-13 is sqrt((x+13)/3),-sqrt((x+13)/3)