What is the inverse of f(x)=(x^2+3)/(x-2) ?

The inverse of f(x)=(x^2+3)/(x-2) is (x+sqrt(x^2-4(3+2x)))/2 ,(x-sqrt(x^2-4(3+2x)))/2

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inverse of f(x)=(x^2+3)/(x-2)

inverse

f (x) = \frac{x ^{2} + 3}{x - 2}

\frac{x + x ^{2} - 4 ( 3 + 2 x )}{2}, \frac{x - x ^{2} - 4 ( 3 + 2 x )}{2}

Solution steps

y = \frac{x ^{2} + 3}{x - 2}

Replace

x

with

y

x = \frac{y ^{2} + 3}{y - 2}

Solve for

y, x = \frac{y ^{2} + 3}{y - 2}

\frac{x + x ^{2} - 4 ( 3 + 2 x )}{2}, \frac{x - x ^{2} - 4 ( 3 + 2 x )}{2}

3 ln (5 - x) - 2

11.5 - 5 t

f (x) = 4 - 7 e^{2 x}

a^{4} - 6 a^{2} + 1

\frac{3 x + 5}{7}

What is the inverse of f(x)=(x^2+3)/(x-2) ?
The inverse of f(x)=(x^2+3)/(x-2) is (x+sqrt(x^2-4(3+2x)))/2 ,(x-sqrt(x^2-4(3+2x)))/2