What is the inverse of f(x)=2x^2+4x-7 ?

The inverse of f(x)=2x^2+4x-7 is (-4+sqrt(8x+72))/4 ,(-4-sqrt(8x+72))/4

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inverse of f(x)=2x^2+4x-7

inverse

f (x) = 2 x^{2} + 4 x - 7

\frac{- 4 + 8 x + 72}{4}, \frac{- 4 - 8 x + 72}{4}

Solution steps

y = 2 x^{2} + 4 x - 7

Replace

x

with

y

x = 2 y^{2} + 4 y - 7

Solve for

y, x = 2 y^{2} + 4 y - 7

\frac{- 4 + 8 x + 72}{4}, \frac{- 4 - 8 x + 72}{4}

f (x) = \frac{1}{2 - sin ( 3 x )}

f (x) = 12 - 2 x - \frac{3}{2}

y = x^{2} - 4 x, x \leq 0

f (x) = 2 \cdot 1 0^{x}

What is the inverse of f(x)=2x^2+4x-7 ?
The inverse of f(x)=2x^2+4x-7 is (-4+sqrt(8x+72))/4 ,(-4-sqrt(8x+72))/4