What is the inverse of (x^2-16)/(2x^2) ?

The inverse of (x^2-16)/(2x^2) is sqrt(-(16)/(2x-1)),-sqrt(-(16)/(2x-1))

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inverse of (x^2-16)/(2x^2)

inverse

\frac{x ^{2} - 16}{2 x ^{2}}

- \frac{16}{2 x - 1}, - - \frac{16}{2 x - 1}

Solution steps

y = \frac{x ^{2} - 16}{2 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 16}{2 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 16}{2 y ^{2}}

- \frac{16}{2 x - 1}, - - \frac{16}{2 x - 1}

f (x) = \frac{5}{8 x}

f (x) = lo g_{2} (x - 1) + 5

cos^{2} (t)

f (x) = x^{5} + 10

\frac{D}{D x} 8 x^{3} - 15 x^{2} - 2, x \geq 1.5

What is the inverse of (x^2-16)/(2x^2) ?
The inverse of (x^2-16)/(2x^2) is sqrt(-(16)/(2x-1)),-sqrt(-(16)/(2x-1))