What is the inverse of f(x)=3+sqrt(2)x-9 ?

The inverse of f(x)=3+sqrt(2)x-9 is (sqrt(2)(x+6))/2

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inverse of f(x)=3+sqrt(2)x-9

inverse

f (x) = 3 + 2 x - 9

\frac{2 ( x + 6 )}{2}

Solution steps

y = 3 + 2 x - 9

Replace

x

with

y

x = 3 + 2 y - 9

Solve for

y, x = 3 + 2 y - 9

\frac{2 ( x + 6 )}{2}

\frac{1}{1 + x ^{2}}

f (x) = \frac{8}{4 + x}

\frac{s + 1}{( s - 1 ) ^{2} + 1}

y = \frac{1}{6} \cdot 1 0^{x - 1} + 5

What is the inverse of f(x)=3+sqrt(2)x-9 ?
The inverse of f(x)=3+sqrt(2)x-9 is (sqrt(2)(x+6))/2