What is the inverse of (2s+5)/((s+1)(s-2)) ?

The inverse of (2s+5)/((s+1)(s-2)) is (s+2+sqrt(9s^2+24s+4))/(2s),(s+2-sqrt(9s^2+24s+4))/(2s)

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inverse of (2s+5)/((s+1)(s-2))

inverse

\frac{2 s + 5}{( s + 1 ) ( s - 2 )}

\frac{s + 2 + 9 s ^{2} + 24 s + 4}{2 s}, \frac{s + 2 - 9 s ^{2} + 24 s + 4}{2 s}

Solution steps

y = \frac{2 s + 5}{( s + 1 ) ( s - 2 )}

Replace

s

with

y

s = \frac{2 y + 5}{( y + 1 ) ( y - 2 )}

Solve for

y, s = \frac{2 y + 5}{( y + 1 ) ( y - 2 )}

\frac{s + 2 + 9 s ^{2} + 24 s + 4}{2 s}, \frac{s + 2 - 9 s ^{2} + 24 s + 4}{2 s}

f (x) = 3 x - 2

f (x) = - \frac{3}{5} x + 5

h (x) = \frac{2 x}{2 x + 3}

16 + 1.5 n

f (x) = (x^{3} + 5)^{\frac{1}{5}} - 5

What is the inverse of (2s+5)/((s+1)(s-2)) ?
The inverse of (2s+5)/((s+1)(s-2)) is (s+2+sqrt(9s^2+24s+4))/(2s),(s+2-sqrt(9s^2+24s+4))/(2s)