What is the inverse of f(x)=((x-5))/(2x+1) ?

The inverse of f(x)=((x-5))/(2x+1) is (-5-x)/(2x-1)

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inverse of f(x)=((x-5))/(2x+1)

inverse

f (x) = \frac{( x - 5 )}{2 x + 1}

\frac{- 5 - x}{2 x - 1}

Solution steps

y = \frac{x - 5}{2 x + 1}

Replace

x

with

y

x = \frac{y - 5}{2 y + 1}

Solve for

y, x = \frac{y - 5}{2 y + 1}

\frac{- 5 - x}{2 x - 1}

\frac{2 x ^{2} + 2 x}{- 3 x ^{2} - 18 x - 15}

f (x) = e^{8 x - 6}

f (x) = \frac{- 5 x + 7}{2}

\frac{9}{x + 4}

f (x) = sec^{2} (x)

What is the inverse of f(x)=((x-5))/(2x+1) ?
The inverse of f(x)=((x-5))/(2x+1) is (-5-x)/(2x-1)