What is the inverse of f(x)=3-(x+1)^2 ?

The inverse of f(x)=3-(x+1)^2 is sqrt(-x+3)-1,-sqrt(-x+3)-1

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inverse of f(x)=3-(x+1)^2

inverse

f (x) = 3 - (x + 1)^{2}

- x + 3 - 1, - - x + 3 - 1

Solution steps

y = 3 - (x + 1)^{2}

Replace

x

with

y

x = 3 - (y + 1)^{2}

Solve for

y, x = 3 - (y + 1)^{2}

- x + 3 - 1, - - x + 3 - 1

\frac{4 x ^{2} - 1}{5 - 7 x ^{2}}

f (x) = - \frac{x - 2}{5}

f (x) = - \frac{x - 2}{6}

(t + 1)^{2}

3 - x + 9

What is the inverse of f(x)=3-(x+1)^2 ?
The inverse of f(x)=3-(x+1)^2 is sqrt(-x+3)-1,-sqrt(-x+3)-1