What is the inverse of f(x)=x^2-9x+20 ?

The inverse of f(x)=x^2-9x+20 is (9+sqrt(4x+1))/2 ,(9-sqrt(4x+1))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2-9x+20

inverse

f (x) = x^{2} - 9 x + 20

\frac{9 + 4 x + 1}{2}, \frac{9 - 4 x + 1}{2}

Solution steps

y = x^{2} - 9 x + 20

Replace

x

with

y

x = y^{2} - 9 y + 20

Solve for

y, x = y^{2} - 9 y + 20

\frac{9 + 4 x + 1}{2}, \frac{9 - 4 x + 1}{2}

f (x) = - 4 x - 3

x^{4} - 16 x^{2}

f (x) = 4 arccos (1 - 2 x) + \frac{π}{3}

3 x^{4}

f (x) = 3 (x + 5) 2 - 4

What is the inverse of f(x)=x^2-9x+20 ?
The inverse of f(x)=x^2-9x+20 is (9+sqrt(4x+1))/2 ,(9-sqrt(4x+1))/2