What is the inverse of h(x)=(x-6)/(7x+3) ?

The inverse of h(x)=(x-6)/(7x+3) is (-6-3x)/(7x-1)

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inverse of h(x)=(x-6)/(7x+3)

inverse

h (x) = \frac{x - 6}{7 x + 3}

\frac{- 6 - 3 x}{7 x - 1}

Solution steps

y = \frac{x - 6}{7 x + 3}

Replace

x

with

y

x = \frac{y - 6}{7 y + 3}

Solve for

y, x = \frac{y - 6}{7 y + 3}

\frac{- 6 - 3 x}{7 x - 1}

arctan (\frac{x}{4})

21

f (x) = 5 3 x - 1

\frac{x - 3}{5}

f (x) = 14 - 4 x^{3}

What is the inverse of h(x)=(x-6)/(7x+3) ?
The inverse of h(x)=(x-6)/(7x+3) is (-6-3x)/(7x-1)